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Thread: Wall sign regulatons: any that decrease maximum area gracefully?

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    Cyburbia Administrator Dan's avatar
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    Wall sign regulatons: any that decrease maximum area gracefully?

    I thought I was something of a sign regulation expert. I'm a bit stumped with this, though.

    Anyhow, many sign regulations use a formula like this to determine the maximum area of wall signs:

    Maximum sign area = 1 x linear foot of wall where sign will be placed
    Maximum sign area = 0.3 x linear meter of wall where sign will be placed

    These have a rather inelegant solution for long walls, where 600 square feet of signage would be inappropriate on a 600' long wall; they'll have a fixed maximum.

    I'm wondering if there are any wall sign area requirements that decrease the maximum sign area per linear wall foot gracefully. Not so much "1'2 x linear foot of wall where sign will be placed up to 200 feet, and then 0.5'2 for each additional linear foot to 400', and then 0.25'2 for each additional linear foot to 600", but something a bit simpler.
    Growth for growth's sake is the ideology of the cancer cell. -- Edward Abbey

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    Cyburbian
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    That's a great idea, Dan, but I haven't seen it. I've seen linear feet formulas that have a maximum...but not your idea. I think you should try to figure out a formula and sell it to all of us.

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    Cyburbian Tide's avatar
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    Most wall sign formulas I've dealt with are in % of total facade or wall, like 7 or 10%. Don't know if you can work that up with a max sq. footage?

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    Cyburbia Administrator Dan's avatar
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    Looking around online, it looks like most formulas to create curves like this ...

    Code:
    |                                                                              
    |                                                    x                      x
    |                                     x
    |                       x
    |               x
    |          x
    |      x
    |   x
    |x
    ---------------------------------------------------------------
    ... involve trigonometry in some form, or as a hack, square roots. I really don't want to introduce advanced math functions into a code that we're trying to keep simple, so I might just use the less granular kludge I described in the first post. Here's what I'm going to use ...

    Front/façade: = 0.75’2 × façade frontage ft for 1st 100 linear ft
    0.5‘2 × linear wall ft for 2nd 100'
    0.25’2 × linear wall ft beyond 200’
    Side and rear walls: 0.25’2 × wall frontage ft
    Growth for growth's sake is the ideology of the cancer cell. -- Edward Abbey

  5. #5
    Cyburbian Streck's avatar
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    I see your point, but of course 600 feet is two football fields long!

    They may want to have a 300 square foot sign at the other end, too.

    I think you have good proportion of sign to building, and would not try to complicate it. Even if you did insert a % reduction factor in there, you would probably still get a 560 sq ft sign right up front!

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