# What are the solutions to the quadratic equation 6x^{2} + 24x = 0?

An equation in the form of ax^{2 }+ bx + c = 0 is a quadratic equation when a ≠ 0.

## Answer: The solutions are 0 and - 4 for equation 6x^{2} + 24x = 0.

Let's solve step by step to find the solutions to the quadratic equation 6x^{2} + 24x = 0.

**Explanation:**

Given that 6x^{2} + 24x = 0

The quadratic formula is given by x = (- b ± √ b^{2} + 4ac) / 2

As we know that coefficient of x^{2 } is a, coefficient of x is b and constant term is c, so, a = 6, b = 24 and c = 0.

Using the quadratic formula, we get,

⇒ - 24 ± √ (24)^{2 }+ 4 ( 6 ) 0 / 2 (6)

⇒ - 24 ± √576^{ } / 12

We can have two values of 'x' when we find square root.

⇒ x = - 24 + √576^{ } / 12 or x = - 24 - √576 / 12

⇒ x = (- 24 + 24) / 12 or x = (- 24 - 24) / 12

⇒ x = 0 / 12 or x = - 48 / 12

⇒ x = 0 or - 4